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20x^2+35x-10=0
a = 20; b = 35; c = -10;
Δ = b2-4ac
Δ = 352-4·20·(-10)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-45}{2*20}=\frac{-80}{40} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+45}{2*20}=\frac{10}{40} =1/4 $
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